Why is USD to CAD more than CAD to USD?
How does this work?
USD/CAD close:1.35206 -->35.2%
CAD/USD close:0.73988 -->27.0%
Why is USD to CAD more than CAD to USD?
How does this work?
USD/CAD close:1.35206 -->35.2%
CAD/USD close:0.73988 -->27.0%
USDCAD: 1.35206 as a %, equals 1.35206 / 1 = 135%
CADUSD: .73988 as a %, equals 1 / .73988 = 135% [another way to say this is that 1 USD equals 135% of 1 CAD, or that 1 CAD equals 73.9% of 1 USD]
It is common to think of the % being "1.00 - .739 = 27.1%". However, that is only a close approximation, when the rates are close to 'parity'. The further out from $1:$1 you are, the less correct that is.
Consider an example where the USDCAD rate is 2 CAD for every 1 USD.
USDCAD would be 2.00, which as a % equals 200%. This means 1 USD is worth 200% of 1 CAD [ie: it is worth twice as much].
CADUSD would be 0.50, which as a % equals 50%. This means 1 CAD is worth 50% of 1 USD [ie: it is worth half as much].
Well, let's first do a bit of math:
1.35206 * .73988 = 1.0003621528
Now round that to two decimal places and you get 1.00. In other words, if you convert both ways, you get back to where you started (with reasonable rounding).
Another example, with easier math.
Add 25% one way and subtract 20% to get back to where you started. The reason is that you start from different bases. Or subtract 20% and then add 25%.
Take $100. Add 25% or $25 and you get $125. 80% of that is $100 because 20% of $125 is $25.
Or take $100. Subtract 20% or $20 and you get $80. 125% of that is $100 because 25% of $80 is $20.
You always have to add a higher percentage than you subtract going the other way. Because when you add, you make the base bigger. So if you did the same percentage, you'd subtract a bigger number. E.g.
$100 * 25% = $25
$100 + $25 = $125
$125 * 25% = $31.25
$125 - $31.25 = $93.75
Or when you subtract then add, you add a smaller number than you subtract
$100 * 20% = $20
$100 - $20 = $80
$80 * 20% = $16
$80 + $16 = $96
The only time the currency percentages should match is when they are both 0%. Otherwise, the exchange rates should be multiplicative inverses.
If as a US dollar holder, it costs me $3 to buy 4 Canadian dollars, (.75), does it stand to reason that my friend to the north would need to spend $4 CAD to buy the $3 US (1.33)?
Converting to percents or premium only obfuscates the issue. it's not magic, it's simple arithmetic.